Formelsammlung komplett

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Thomas Ba. 13 years ago
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\usepackage[
pdftitle={Formelsammlung Wahrscheinlichkeitstheorie und Statistik},
pdfsubject={Formelsammlung "Wahrscheinlichkeitstheorie und Statistik"},
pdfauthor={},
pdfauthor={Friesen und Battermann},
pdfkeywords={Wahrscheinlichkeitstheorie und Statistik, Formelsammlung},
pdfborder={0 0 0}
]{hyperref}
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\fancyhf{} %alle Kopf- und Fußzeilenfelder bereinigen
\fancyhead[L]{Formelsammlung} %zentrierte Kopfzeile
\fancyhead[C]{Wahrscheinlichkeitstheorie und Statistik} %Kopfzeile links
\fancyhead[R]{WS 2011/2012} %Kopfzeile rechts
\fancyhead[R]{Seite \thepage\ von \pageref{LastPage}} %Kopfzeile rechts
\renewcommand{\headrulewidth}{0.4pt} %obere Trennlinie
\newcommand{\spa}{\hspace*{4mm}}
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\title{Formelsammlung Wahrscheinlichkeitstheorie und Statistik}
\author{--}
\date{3. Semester}
\begin{document}
\pagestyle{fancy}
\setcounter{page}{1}
\section*{Wahrscheinlichkeitstheorie und Statistik (Formeln)}
\addcontentsline{toc}{section}{Wahrscheinlichkeitstheorie und Statistik (Formeln)}
\subsection*{Eigenschaften und Rechenregeln für Wahrscheinlichkeit}
\addcontentsline{toc}{subsection}{Eigenschaften und Rechenregeln für Wahrscheinlichkeit}
\section*{Eigenschaften und Rechenregeln für Wahrscheinlichkeit}
\addcontentsline{toc}{section}{Eigenschaften und Rechenregeln für Wahrscheinlichkeit}
\begin{math}
P(\omega) = 1, P(\phi) = 0 \text{ für } A: 0 \le P(A) \le 1\\
P(\Omega) = 1, P(\phi) = 0 \text{ für } A: 0 \le P(A) \le 1\\
\overline{A} = A^C \text{ mit } P(\overline{A}) = 1-P(A) \text{ (Gegenereignis)}\\
P(A\cup B) = P(A) + P(B) - P(A\cap B) \text{ (Vereinigung)}\\
P(A\cup B) = P(A) + P(B) \text{ (Wenn A und B \underline{disjunkt})}
\end{math}
\subsection*{Berechnung von Wahrscheinlichkeit mit Kombinatorik}
\addcontentsline{toc}{subsection}{Berechnung von Wahrscheinlichkeit mit Kombinatorik}
\section*{Berechnung von Wahrscheinlichkeit mit Kombinatorik}
\addcontentsline{toc}{section}{Berechnung von Wahrscheinlichkeit mit Kombinatorik}
\begin{itemize}
\item[1.] Fall:\\
Ziehen mit Zurücklegen, mit Reihenfolge: \( n^k \quad |\omega| = n^k\)
Ziehen mit Zurücklegen, mit Reihenfolge: \( n^k \quad |\Omega| = n^k\)
\item[2.] Fall:\\
Ziehen ohne Zurücklegen, mit Reihenfolge: \( \frac{n!}{(n-k)!} = n^{\underline{k}} \)
\item[3.] Fall:\\
@ -90,15 +85,15 @@
Ziehen mit Zurücklegen, ohne Reihenfolge: \( \binom{n+k-1}{k} \overset{\text{da doof}}{\Rightarrow} n^k \text{ 1. Fall}\)
\end{itemize}
\subsection*{Binomialkoeffizient/Multinomialkoeffizient}
\addcontentsline{toc}{subsection}{Binomialkoeffizient/Multinomialkoeffizient}
\section*{Binomialkoeffizient/Multinomialkoeffizient}
\addcontentsline{toc}{section}{Binomialkoeffizient/Multinomialkoeffizient}
Bi: \(\binom{n}{k} = \frac{n!}{(n-k)!*k!} \)
Multi: \( \frac{n!}{k_1! * k_2! ** k_l!} \) mit \( k_1 + k_2 ++ k_l = n \)
\subsection*{Bedingte Wahrscheinlichkeit und Unabhängigkeit}
\addcontentsline{toc}{subsection}{Bedingte Wahrscheinlichkeit und Unabhängigkeit}
\section*{Bedingte Wahrscheinlichkeit und Unabhängigkeit}
\addcontentsline{toc}{section}{Bedingte Wahrscheinlichkeit und Unabhängigkeit}
\(P(B\mid A) = \frac{P(A\cap B)}{P(A)}\) (wenn \( P(A) \ne 0 \) bedingte Wahrscheinlichkeit und Bedingung)
@ -106,17 +101,198 @@
\( P(A\cap B) = P(A) * P(B) \) (Wenn \(A,B\) unabhängig von einander)
\subsection*{Totale Wahrscheinlichkeit}
\addcontentsline{toc}{subsection}{Totale Wahrscheinlichkeit}
\section*{Totale Wahrscheinlichkeit}
\addcontentsline{toc}{section}{Totale Wahrscheinlichkeit}
Satz: \( P(A) = P(A\mid B_1) * P(B_1) + P(A\mid B_2) * P(B_2) ++ P(A\mid B_k) * P(B_k) \)
\subsection*{Zufallsvariablen}
\addcontentsline{toc}{subsection}{Zufallsvariablen}
\section*{Zufallsvariablen}
\addcontentsline{toc}{section}{Zufallsvariablen}
Eine Zufallsvariable \(X\) ist eine Funktion \(X: \omega \to \mathbb R\)\\
Die Verteilung einer Zufallsvariable gibt an, mit welchen Wahrscheinlichkeiten die Zufallsvariable ihre möglichen Werte annimmt.
\subsection*{Diskrete Zufallsvariable}
\addcontentsline{toc}{subsection}{Diskrete Zufallsvariable}
Diskret: \(X\) nimmt nur einzelne Werte mit bestimmten Wahrscheinlichkeiten an
\subsubsection*{Erwartungswert (Mittelwert)}
\addcontentsline{toc}{subsubsection}{Erwartungswert (Mittelwert)}
\( M = E(X) = \sum\limits_i x_i * p_i \) mit \( (i=1,2,3,…) \)
\subsubsection*{Streuung (Varianz)}
\addcontentsline{toc}{subsubsection}{Streuung (Varianz)}
\( \sigma^2 = V(X) = Var(X) = \sum\limits_i (x_i-\mu)^2 * p_i \to\) mittlerer Quadratischer Abstand
Standardabweichung \(\sigma\) ist \( \sigma = \sqrt{\sigma^2} \)
Wenn \( \sigma = 0 \Rightarrow x = \mu \) mit Wahrscheinlichkeit 1
\( \sigma^2 = \sum\limits_i x_i * p_i - \mu^2 \) (einfachere Formel)
Variationskoeffizient \(\frac{\sigma}{\mu}\) in (\%)
\section*{Verteilung und Verteilungsfunktion von Zufallsvariablen}
\addcontentsline{toc}{section}{Verteilung und Verteilungsfunktion von Zufallsvariablen}
Funktion \(F: \mathbb R \to [0,1] \) mit \( F(x) = P(X \le x) \)
\subsection*{Eigenschaften von \(F(x)\)}
\addcontentsline{toc}{subsection}{Eigenschaften von \(F(x)\)}
\begin{itemize}
\item \( \lim\limits_{x\to-\infty} F(x) = 0 \) und \( \lim\limits_{x\to\infty} F(x) = 1 \)
\item \(F(x)\) ist monoton Wachsend (nicht unbedingt streng)
\item \(F(x)\) ist rechtsseitig stetig \( (F(x) ? P(X\le c) )\)
\end{itemize}
\subsection*{Verteilungsfunktion}
\addcontentsline{toc}{subsection}{Verteilungsfunktion}
\begin{itemize}
\item eine Treppenfunktion \(\to\) bei diskreten Verteilungen
\item eine durchgehend stetige Funktion \(\to\) Keine Sprünge
\end{itemize}
\section*{Stetige Verteilung}
\addcontentsline{toc}{section}{Stetige Verteilung}
\begin{itemize}
\item stetige Funktion \(F(x)\)
\item \(P(X=x) = 0 \forall x \in\mathbb R \) (\(\Rightarrow\) Keine Sprünge)
\end{itemize}
Stetige Stetige Verteilungsfunktionen besitzen eine Dichtefunktion \(f(x)\) mit
\begin{itemize}
\item \(f(x) = F'(x)\)
\end{itemize}
\subsection*{Eigenschaften Dichtefunktion}
\addcontentsline{toc}{subsection}{Eigenschaften Dichtefunktion}
\begin{itemize}
\item \( f: \mathbb R \to \left[0,\infty\right)\), also \(f(x) \ge 0 \forall x \in \mathbb R \)
\item \( \int\limits_{-\infty}^\infty f(x) \mathrm dx = 1\)
\end{itemize}
\section*{Diskrete Verteilung}
\addcontentsline{toc}{section}{Diskrete Verteilung}
Gleichverteilung: \( P(X=x_1) = P(X=x_2) == P(X=x_n) = \frac1n \)
\section*{Geometrische Verteilung}
\addcontentsline{toc}{section}{Geometrische Verteilung}
\(X\) ist geometrisch verteilt mit Parameter \(p\): \(P(X=k) = (1-p)^{k-1}*p \)
\section*{Binomialverteilung}
\addcontentsline{toc}{section}{Binomialverteilung}
Ein Zufallsexperiment wird \(n\)-mal unabhängig voneinander wiederholt\\
\( P(X=k) = \binom{n}{k} * p^k *(1-p)^{n-k} \)
\begin{itemize}
\item \(\mu = \sum\limits_{k=0}^n k * \binom{n}{k} *p^k * (1-p)^{n-k} = n*p \)
\item \(\sigma^2 = n*p*(1-p) \)
\end{itemize}
für \( p = 0,5 \) ist die Verteilung Symmetrisch
\section*{Gaußsche Normalverteilung}
\addcontentsline{toc}{section}{Gaußsche Normalverteilung}
\(f(x) = \frac{1}{\sqrt{2\pi} * \sigma} *e^{-\frac12*(\frac{\pi-\mu}{\sigma})^2} \)
Veränderung von \(\mu\to\) Verschiebung ind \(x\)-Richtung
Veränderung von \(\sigma\to\) Stauchung/Dehnung in der Breite/Höhe
Standardnormalverteilung: \( N(0,1): F(x) = \frac{1}{\sqrt{2\pi}} * e^{-\frac12x^2} \)
\section*{Erwartungswert und Varianz stetiger Verteilung}
\addcontentsline{toc}{section}{Erwartungswert und Varianz stetiger Verteilung}
\underline{diskret:} \( \mu = \sum\limits_i x_i * p_i \quad \sigma^2 = \sum\limits_i x_i^2 * p_i -\mu^2 \)
\underline{stetig:} \( \mu = \int\limits_{-\infty}^\infty x * f(x) \mathrm dx \quad \sigma^2 = \int\limits_{-\infty}^\infty x^2 * f(x) \mathrm dx - \mu^2 \)
\section*{Normalverteilung}
\addcontentsline{toc}{section}{Normalverteilung}
Wenn \(f(x) \in X\), dann \(X\) ist \(N(\mu,\sigma)\) verteilt.
Es gilt: \( E(X) = \mu, Var(X) = \sigma^2 \)
\(\Rightarrow X\) heißt standardnormalverteilt, wenn \(\mu = 0, \sigma = 1 \Rightarrow f(x) = \frac{1}{\sqrt{2\pi}}*e^{-\frac12x^2} \)
Verteilungsfunktion \(F(x) = \phi(x) = \phi_{0,1}(x) \to \) hierfür: Tabellenwerte
\includegraphics{bilder/fosa_dichtefunktion.eps}
\section*{Schätzungen und Tests}
\addcontentsline{toc}{section}{Schätzungen und Tests}
\subsection*{Stichproben}
\addcontentsline{toc}{subsection}{Stichproben}
\begin{itemize}
\item arithmetisches Mittel (Durchschnitt)\\
\( \overline{x} = \frac1n * (x_1+x_2++x_n) = \frac1n \sum\limits_{i=1}^n x_i \)
\item Schätzung für \(\mu\)\\
\( \overline{x} = \frac1n * (x_1+x_2++x_n) \)
\item Schätzwert für \(\sigma\)\\
\( s^2 = \frac{1}{n-1} * (x_1^2 + x_2^2 ++ x_n^2 ) - \frac{n}{n-1} * \overline{x}^2 = \sqrt{s_{n-1}^2} \)
\end{itemize}
\subsection*{Zentraler Grenzwertsatz}
\addcontentsline{toc}{subsection}{Zentraler Grenzwertsatz}
\( \overline{x} = \frac1n * (x_1+x_2++x_n) \)
\( \frac{\overline{x}-\mu}{\sigma} * \sqrt{n} \) ist für große \(n\) näherungsweise \(N(0,1)\) verteilt.
\subsection*{Tests}
\addcontentsline{toc}{subsection}{Tests}
\( H_0: \mu = \mu_0 \Rightarrow \) zweiseitiger Test
\( H_0: \mu \le \mu_0 \) oder \( H_0: \mu \ge \mu_0 \Rightarrow \) einseitige Tests
\( T= \frac{\overline{x}-\mu_0}{\sigma} * \sqrt{n} \)
\includegraphics{bilder/fosa_dichtefunktion_zwei.eps}\\
zweiseitiger Test
Testentscheidung: \(H_0\) wird \(\begin{cases} \text{angenommen} &, -c \le T \le c \\ \text{abgelehnt} &, T>c,T<-c \end{cases} \)
\underline{Bestimmung von \(c\)}
\( \phi(c) = 1-\frac\alpha2,\quad c=\phi^{-1}(1-\frac\alpha2) \) (rückwärts)
\underline{Einseitige Tests}
\(H_0: \mu \le \mu_0 \) (vorgegebener Maximalwert)
\includegraphics{bilder/fosa_dichtefunktion_max.eps}
\(H_0\) wird \(\begin{cases} \text{angenommen} &, T \le c \\ \text{abgelehnt} &, T>c \end{cases} \)
\(H_0: \mu \ge \mu_0 \) (vorgegebener Minimalwert)
\includegraphics{bilder/fosa_dichtefunktion_min.eps}
\(H_0\) wird \(\begin{cases} \text{angenommen} &, T \ge c \\ \text{abgelehnt} &, T<c \end{cases} \)
\subsection*{Konfidenzintervall}
\addcontentsline{toc}{subsection}{Konfidenzintervall}
Konfidenzintervall (Vertrauensintervall) für den Erwartungswert $\mu$ $\to$ Intervall, das um den Stichproben-Schätzwert $\overline{x}$ herumliegt, in dem $\mu$ mit Wahrscheinlichkeit \cunder{Yellow}{$1-\alpha$} liegt.
Analog zu den Tests (zweiseitig): $P(-c \le T \le c) = 1-\alpha$\\
$\to \underbrace{P\Big(-\phi^{-1}(1-\frac\alpha2) \le \underbrace{T}_{ \frac{\overline{x}-\mu}{\sigma} * \sqrt{n} } \le \phi^{-1}(1-\frac\alpha2) \Big) }_{\color{Orange}\text{Umformen, so dass } \mu \text{ in der Mitte steht}}$\\
$\to P\Big( \overline{x}-\phi^{-1}(1-\frac{\alpha}{2}) * \frac{\sigma}{\sqrt{n}}\ \le\ \mu\ \le\ \overline{x}+\phi^{-1}(1-\frac{\alpha}{2}) * \frac{\sigma}{\sqrt{n}}\Big)$\\
$\to$ Formel für das $(1-\alpha)$ Konfidenzintervall:\\
$ \Big[ \overline{x}-\phi^{-1}(1-\frac{\alpha}{2}) * \frac{\sigma}{\sqrt{n}}\ ,\ \overline{x}+\phi^{-1}(1-\frac{\alpha}{2}) * \frac{\sigma}{\sqrt{n}} \Big] $ \textcolor{Orange}{$\leftarrow$ da drin liegt $\mu$ mit Wahrscheinlichkeit $1-\alpha$}\\
\includegraphics{bilder/1-6_konfidenz.eps}
\end{document}

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80.057 704 s
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<symbolsize name="small" value="2"/>
<symbolsize name="tiny" value="1.1"/>
<arrowsize name="large" value="10"/>
<arrowsize name="small" value="5"/>
<arrowsize name="tiny" value="3"/>
<color name="red" value="1 0 0"/>
<color name="green" value="0 1 0"/>
<color name="blue" value="0 0 1"/>
<color name="yellow" value="1 1 0"/>
<color name="orange" value="1 0.647 0"/>
<color name="gold" value="1 0.843 0"/>
<color name="purple" value="0.627 0.125 0.941"/>
<color name="gray" value="0.745"/>
<color name="brown" value="0.647 0.165 0.165"/>
<color name="navy" value="0 0 0.502"/>
<color name="pink" value="1 0.753 0.796"/>
<color name="seagreen" value="0.18 0.545 0.341"/>
<color name="turquoise" value="0.251 0.878 0.816"/>
<color name="violet" value="0.933 0.51 0.933"/>
<color name="darkblue" value="0 0 0.545"/>
<color name="darkcyan" value="0 0.545 0.545"/>
<color name="darkgray" value="0.663"/>
<color name="darkgreen" value="0 0.392 0"/>
<color name="darkmagenta" value="0.545 0 0.545"/>
<color name="darkorange" value="1 0.549 0"/>
<color name="darkred" value="0.545 0 0"/>
<color name="lightblue" value="0.678 0.847 0.902"/>
<color name="lightcyan" value="0.878 1 1"/>
<color name="lightgray" value="0.827"/>
<color name="lightgreen" value="0.565 0.933 0.565"/>
<color name="lightyellow" value="1 1 0.878"/>
<dashstyle name="dashed" value="[4] 0"/>
<dashstyle name="dotted" value="[1 3] 0"/>
<dashstyle name="dash dotted" value="[4 2 1 2] 0"/>
<dashstyle name="dash dot dotted" value="[4 2 1 2 1 2] 0"/>
<textsize name="large" value="\large"/>
<textsize name="Large" value="\Large"/>
<textsize name="LARGE" value="\LARGE"/>
<textsize name="huge" value="\huge"/>
<textsize name="Huge" value="\Huge"/>
<textsize name="small" value="\small"/>
<textsize name="footnote" value="\footnotesize"/>
<textsize name="tiny" value="\tiny"/>
<textstyle name="center" begin="\begin{center}" end="\end{center}"/>
<textstyle name="itemize" begin="\begin{itemize}" end="\end{itemize}"/>
<textstyle name="item" begin="\begin{itemize}\item{}" end="\end{itemize}"/>
<gridsize name="4 pts" value="4"/>
<gridsize name="8 pts (~3 mm)" value="8"/>
<gridsize name="16 pts (~6 mm)" value="16"/>
<gridsize name="32 pts (~12 mm)" value="32"/>
<gridsize name="10 pts (~3.5 mm)" value="10"/>
<gridsize name="20 pts (~7 mm)" value="20"/>
<gridsize name="14 pts (~5 mm)" value="14"/>
<gridsize name="28 pts (~10 mm)" value="28"/>
<gridsize name="56 pts (~20 mm)" value="56"/>
<anglesize name="90 deg" value="90"/>
<anglesize name="60 deg" value="60"/>
<anglesize name="45 deg" value="45"/>
<anglesize name="30 deg" value="30"/>
<anglesize name="22.5 deg" value="22.5"/>
<tiling name="falling" angle="-60" step="4" width="1"/>
<tiling name="rising" angle="30" step="4" width="1"/>
</ipestyle>
<page>
<layer name="alpha"/>
<view layers="alpha" active="alpha"/>
<path layer="alpha" stroke="black">
64 708 m
96 708
112 712
120 720
124 752
128 756
128 756 s
</path>
<path matrix="-1 0 0 1 256 0" stroke="black">
64 708 m
96 708
112 712
120 720
124 752
128 756
128 756 s
</path>
<path stroke="black" arrow="normal/normal">
128 700 m
128 768 l
</path>
<path stroke="black" arrow="normal/normal">
56 704 m
200 704 l
</path>
<path fill="darkgray" tiling="rising">
64 708 m
80.2511 708.082 l
80.3468 704 l
64.0993 704 l
64.0993 708 l
64 708 l
</path>
<path fill="darkgray" tiling="rising">
192 708 m
176.003 708.077 l
176.111 704 l
192.168 704 l
192 708 l
192 708 l
</path>
<text transformations="translations" pos="80 696" stroke="darkgray" type="label" width="12.06" height="5.812" depth="0.83" valign="baseline">$-c$</text>
<text transformations="translations" pos="176 696" stroke="darkgray" type="label" width="4.311" height="4.289" depth="0" valign="baseline">$c$</text>
<text matrix="1 0 0 1 -8 4" transformations="translations" pos="64 712" stroke="darkgray" type="label" width="39.859" height="6.25" depth="3.04" valign="baseline" size="small">Fl$\ddot a$che $\frac{\alpha}{2}$ </text>
<text matrix="1 0 0 1 88 4" transformations="translations" pos="64 712" stroke="darkgray" type="label" width="36.787" height="6.25" depth="3.04" valign="baseline" size="small">Fl$\ddot a$che $\frac{\alpha}{2}$</text>
<path fill="black" tiling="falling">
80.2511 708.082 m
96 708
112 712
120 720
124 752
128 756
132 752
136 720
144 712
160 708
176.003 708.077
176.003 708.077
176.111 704
176.111 704
128 704
128 704
80.3468 704
80.3468 704
80.2511 708.082 s
</path>
<text matrix="1 0 0 1 -8 -4" transformations="translations" pos="144 748" stroke="black" type="label" width="82.821" height="6.727" depth="3.04" valign="baseline" size="small">Fl$\ddot a$che $\phi(x) = 1-\frac{\alpha}{2}$</text>
</page>
</ipe>
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